Optimal. Leaf size=143 \[ \frac{c x \left (a+b x^4\right )^{p+1} \, _2F_1\left (1,p+\frac{5}{4};\frac{5}{4};-\frac{b x^4}{a}\right )}{a}+\frac{d x^2 \left (a+b x^4\right )^{p+1} \, _2F_1\left (1,p+\frac{3}{2};\frac{3}{2};-\frac{b x^4}{a}\right )}{2 a}+\frac{e x^3 \left (a+b x^4\right )^{p+1} \, _2F_1\left (1,p+\frac{7}{4};\frac{7}{4};-\frac{b x^4}{a}\right )}{3 a}+\frac{f \left (a+b x^4\right )^{p+1}}{4 b (p+1)} \]
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Rubi [A] time = 0.131025, antiderivative size = 170, normalized size of antiderivative = 1.19, number of steps used = 12, number of rules used = 8, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.32, Rules used = {1885, 1204, 246, 245, 365, 364, 1248, 641} \[ c x \left (a+b x^4\right )^p \left (\frac{b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac{1}{4},-p;\frac{5}{4};-\frac{b x^4}{a}\right )+\frac{1}{2} d x^2 \left (a+b x^4\right )^p \left (\frac{b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac{1}{2},-p;\frac{3}{2};-\frac{b x^4}{a}\right )+\frac{1}{3} e x^3 \left (a+b x^4\right )^p \left (\frac{b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac{3}{4},-p;\frac{7}{4};-\frac{b x^4}{a}\right )+\frac{f \left (a+b x^4\right )^{p+1}}{4 b (p+1)} \]
Antiderivative was successfully verified.
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Rule 1885
Rule 1204
Rule 246
Rule 245
Rule 365
Rule 364
Rule 1248
Rule 641
Rubi steps
\begin{align*} \int \left (c+d x+e x^2+f x^3\right ) \left (a+b x^4\right )^p \, dx &=\int \left (\left (c+e x^2\right ) \left (a+b x^4\right )^p+x \left (d+f x^2\right ) \left (a+b x^4\right )^p\right ) \, dx\\ &=\int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx+\int x \left (d+f x^2\right ) \left (a+b x^4\right )^p \, dx\\ &=\frac{1}{2} \operatorname{Subst}\left (\int (d+f x) \left (a+b x^2\right )^p \, dx,x,x^2\right )+\int \left (c \left (a+b x^4\right )^p+e x^2 \left (a+b x^4\right )^p\right ) \, dx\\ &=\frac{f \left (a+b x^4\right )^{1+p}}{4 b (1+p)}+c \int \left (a+b x^4\right )^p \, dx+\frac{1}{2} d \operatorname{Subst}\left (\int \left (a+b x^2\right )^p \, dx,x,x^2\right )+e \int x^2 \left (a+b x^4\right )^p \, dx\\ &=\frac{f \left (a+b x^4\right )^{1+p}}{4 b (1+p)}+\left (c \left (a+b x^4\right )^p \left (1+\frac{b x^4}{a}\right )^{-p}\right ) \int \left (1+\frac{b x^4}{a}\right )^p \, dx+\frac{1}{2} \left (d \left (a+b x^4\right )^p \left (1+\frac{b x^4}{a}\right )^{-p}\right ) \operatorname{Subst}\left (\int \left (1+\frac{b x^2}{a}\right )^p \, dx,x,x^2\right )+\left (e \left (a+b x^4\right )^p \left (1+\frac{b x^4}{a}\right )^{-p}\right ) \int x^2 \left (1+\frac{b x^4}{a}\right )^p \, dx\\ &=\frac{f \left (a+b x^4\right )^{1+p}}{4 b (1+p)}+c x \left (a+b x^4\right )^p \left (1+\frac{b x^4}{a}\right )^{-p} \, _2F_1\left (\frac{1}{4},-p;\frac{5}{4};-\frac{b x^4}{a}\right )+\frac{1}{2} d x^2 \left (a+b x^4\right )^p \left (1+\frac{b x^4}{a}\right )^{-p} \, _2F_1\left (\frac{1}{2},-p;\frac{3}{2};-\frac{b x^4}{a}\right )+\frac{1}{3} e x^3 \left (a+b x^4\right )^p \left (1+\frac{b x^4}{a}\right )^{-p} \, _2F_1\left (\frac{3}{4},-p;\frac{7}{4};-\frac{b x^4}{a}\right )\\ \end{align*}
Mathematica [A] time = 0.111298, size = 147, normalized size = 1.03 \[ \frac{1}{12} \left (a+b x^4\right )^p \left (12 c x \left (\frac{b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac{1}{4},-p;\frac{5}{4};-\frac{b x^4}{a}\right )+6 d x^2 \left (\frac{b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac{1}{2},-p;\frac{3}{2};-\frac{b x^4}{a}\right )+4 e x^3 \left (\frac{b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac{3}{4},-p;\frac{7}{4};-\frac{b x^4}{a}\right )+\frac{3 f \left (a+b x^4\right )}{b (p+1)}\right ) \]
Antiderivative was successfully verified.
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Maple [F] time = 0.25, size = 0, normalized size = 0. \begin{align*} \int \left ( f{x}^{3}+e{x}^{2}+dx+c \right ) \left ( b{x}^{4}+a \right ) ^{p}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (f x^{3} + e x^{2} + d x + c\right )}{\left (b x^{4} + a\right )}^{p}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (f x^{3} + e x^{2} + d x + c\right )}{\left (b x^{4} + a\right )}^{p}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 70.5717, size = 141, normalized size = 0.99 \begin{align*} \frac{a^{p} c x \Gamma \left (\frac{1}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{4}, - p \\ \frac{5}{4} \end{matrix}\middle |{\frac{b x^{4} e^{i \pi }}{a}} \right )}}{4 \Gamma \left (\frac{5}{4}\right )} + \frac{a^{p} d x^{2}{{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, - p \\ \frac{3}{2} \end{matrix}\middle |{\frac{b x^{4} e^{i \pi }}{a}} \right )}}{2} + \frac{a^{p} e x^{3} \Gamma \left (\frac{3}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{3}{4}, - p \\ \frac{7}{4} \end{matrix}\middle |{\frac{b x^{4} e^{i \pi }}{a}} \right )}}{4 \Gamma \left (\frac{7}{4}\right )} + f \left (\begin{cases} \frac{a^{p} x^{4}}{4} & \text{for}\: b = 0 \\\frac{\begin{cases} \frac{\left (a + b x^{4}\right )^{p + 1}}{p + 1} & \text{for}\: p \neq -1 \\\log{\left (a + b x^{4} \right )} & \text{otherwise} \end{cases}}{4 b} & \text{otherwise} \end{cases}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (f x^{3} + e x^{2} + d x + c\right )}{\left (b x^{4} + a\right )}^{p}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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